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75 lines (66 loc) · 2.09 KB
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/**
* Finds the maximum subarray using the divide and conquer algorithm
* by Bentley, Jon (1984) (complexity O(n(logn)));
*/
(function (exports) {
'use strict';
/**
* Accepts an array and range. Finds the maximum sum of elements
* around the middle of the range.
*
* @param {array} array
* @param {number} left - the left interval of the range
* @param {number} middle - the middle of the range
* @param {number} right - the right side of the range
* @return {number} the maximum sum including the middle element
*/
function crossSubarray(array, left, middle, right) {
var leftSum = -Infinity,
rightSum = -Infinity,
sum = 0,
i;
for (i = middle; i >= left; i -= 1) {
if (sum + array[i] >= leftSum) {
leftSum = sum + array[i];
}
sum += array[i];
}
sum = 0;
for (i = middle + 1; i < right; i += 1) {
if (sum + array[i] >= rightSum) {
rightSum = sum + array[i];
}
sum += array[i];
}
return leftSum + rightSum;
}
/**
* Using divide and conquer finds the maximum sum of subarray of the given
*
* @param {array} array
* @param {number} left side of the range
* @param {number} the right side of the range
* @return {number} the maximum sum of the elements of
* subarray whithin the given range
*/
function maxSubarrayPartitioner(array, left, right) {
if (right - left <= 1) {
return array[left];
}
var middle = Math.floor((left + right) / 2),
leftSum = maxSubarrayPartitioner(array, left, middle),
rightSum = maxSubarrayPartitioner(array, middle, right),
crossSum = crossSubarray(array, left, middle, right);
return Math.max(crossSum, leftSum, rightSum);
}
/**
* Returns the maximum sum of the elements of a subarray of the given array
*
* @param {array} the array
* @return the maximum sum
*/
function maxSubarray(array) {
return maxSubarrayPartitioner(array, 0, array.length);
}
exports.maxSubarray = maxSubarray;
}(typeof exports === 'undefined' ? window : exports));