// Dynamic Programming Python implementation of Matrix
// Chain Multiplication.
public class MatrixChainMultiplication {
// Matrix Ai has dimension p[i-1] x p[i] for i = 1..n
		static int MatrixChainOrder(int p[], int n) {
			/* For simplicity of the program, one extra row and one
			extra column are allocated in m[][].  0th row and 0th
			column of m[][] are not used */
			int m[][] = new int[n][n];

			int i, j, k, L, q;

			/* m[i,j] = Minimum number of scalar multiplications needed
			to compute the matrix A[i]A[i+1]...A[j] = A[i..j] where
			dimension of A[i] is p[i-1] x p[i] */

			// cost is zero when multiplying one matrix.
			for (i = 1; i < n; i++)
				m[i][i] = 0;

			// L is chain length.
			for (L=2; L<n; L++) {
				for (i=1; i<n-L+1; i++) {
					j = i+L-1;
					if(j == n) continue;
					m[i][j] = Integer.MAX_VALUE;
					for (k=i; k<=j-1; k++) {
					// q = cost/scalar multiplications
						q = m[i][k] + m[k+1][j] + p[i-1]*p[k]*p[j];
						if (q < m[i][j])
							m[i][j] = q;
					}
				}
			}
		return m[1][n-1];
		}

		// Driver program to test above function
		public static void main(String args[]) {
			int arr[] = new int[] {1, 2, 3, 4};
			int size = arr.length;
			System.out.println("Minimum number of multiplications is "+
			MatrixChainOrder(arr, size));
		}
}